start && end > -1) { if (start > -1) { var res = data.substring(start, end); start = res.indexOf('>') + 1; res = res.substring(start); if (res.length != 0) { eval(res); } } cursor = end + 1; } } } //]]>
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Re: Beethoven A to Z October 24, 2009 01:28AM | Registered: 1 year ago Posts: 698 |
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Re: Beethoven A to Z February 18, 2010 05:09AM | Registered: 1 year ago Posts: 698 |
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